## Work max and delta G

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Jordan_Wesson_2J
Posts: 59
Joined: Fri Sep 28, 2018 12:26 am

### Work max and delta G

How is the maximum work and delta G equal?

Sean_Rodriguez_1J
Posts: 62
Joined: Fri Sep 28, 2018 12:17 am

### Re: Work max and delta G

Delta G is defined as the amount of energy available to do useful work (ie non expansion work) for a spontaneous process under a constant temperature and pressure. Therefore, by definition delta G equals the maximum possible work that the system can do. A proof for this exists that involves some differential calculus if you're interested.
viewtopic.php?t=5141
Attachments
png.latex.png (1.09 KiB) Viewed 38 times
png.latex.png (1.09 KiB) Viewed 38 times
Last edited by Sean_Rodriguez_1J on Thu Feb 21, 2019 9:30 pm, edited 2 times in total.

Parth Mungra
Posts: 72
Joined: Fri Sep 28, 2018 12:28 am

### Re: Work max and delta G

Remember that dG represents all the energy (from a process) that is free to do work. Essentially, this statement is saying that virtually all of the free energy calculated from the Gibbs Free Energy equation is available to do work (the maximum amount)