## Delta G = 0

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Helen Mejia 1I
Posts: 67
Joined: Fri Sep 28, 2018 12:24 am

### Delta G = 0

What does it mean when delta G is equal to zero? Does it have to do something with the amount of work the reaction can do?

Rachel-Weisz3C
Posts: 66
Joined: Fri Sep 28, 2018 12:23 am

### Re: Delta G = 0

I believe that if $\Delta$G is equal to zero the reaction is at equilibrium.

Brandon_Tran_2E
Posts: 63
Joined: Fri Sep 28, 2018 12:23 am

### Re: Delta G = 0

Yes!

Rian Montagh 2K
Posts: 60
Joined: Fri Sep 28, 2018 12:15 am

### Re: Delta G = 0

we also set delta G to 0 when we want to find the minimum temp to make a reaction spontaneous.

Also, a reaction at equilibrium does no work, so at delta G = 0 the reaction can do no work.

Cole Elsner 2J
Posts: 88
Joined: Fri Sep 28, 2018 12:25 am

### Re: Delta G = 0

Reaction is at physical equilibrium, generally =0 at phase changes!

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