Page 1 of 1

### Delta G=0 at equilibrium

Posted: Fri Feb 22, 2019 12:12 am
I understand that at equilibrium, Gibbs free energy change is zero but I'm confused on the conceptual reasoning behind this. Could someone explain this to me?

### Re: Delta G=0 at equilibrium

Posted: Fri Feb 22, 2019 9:27 am
When Gibbs free energy is equal to 0 that means that the reaction is at equilibrium meaning that no more work can be done.

### Re: Delta G=0 at equilibrium

Posted: Fri Feb 22, 2019 11:38 am
Gibbs free energy is the energy free to do work. At equilibrium, no net energy is being gained or lost (nothing is really changing). Thus, at equilibrium, Delta G is 0.

### Re: Delta G=0 at equilibrium

Posted: Fri Feb 22, 2019 2:34 pm
Gibbs free energy is the free energy in a system. When it is 0, there can be no gain or loss of energy.

### Re: Delta G=0 at equilibrium

Posted: Fri Feb 22, 2019 3:37 pm
The total delta G of a reaction equals the total delta G of products minus that of all the reactants. At equilibrium, there is no difference between the delta G of the reactants and the products, so that total delta G equals 0.