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Delta G=0 at equilibrium

Posted: Fri Feb 22, 2019 12:12 am
by Samantha Man 1L
I understand that at equilibrium, Gibbs free energy change is zero but I'm confused on the conceptual reasoning behind this. Could someone explain this to me?

Re: Delta G=0 at equilibrium

Posted: Fri Feb 22, 2019 9:27 am
by Desiree1G
When Gibbs free energy is equal to 0 that means that the reaction is at equilibrium meaning that no more work can be done.

Re: Delta G=0 at equilibrium

Posted: Fri Feb 22, 2019 11:38 am
by Ethan Baurle 1A
Gibbs free energy is the energy free to do work. At equilibrium, no net energy is being gained or lost (nothing is really changing). Thus, at equilibrium, Delta G is 0.

Re: Delta G=0 at equilibrium

Posted: Fri Feb 22, 2019 2:34 pm
by Bruce Chen 2H
Gibbs free energy is the free energy in a system. When it is 0, there can be no gain or loss of energy.

Re: Delta G=0 at equilibrium

Posted: Fri Feb 22, 2019 3:37 pm
by michelle
The total delta G of a reaction equals the total delta G of products minus that of all the reactants. At equilibrium, there is no difference between the delta G of the reactants and the products, so that total delta G equals 0.