Gibbs Free energy

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

deniise_garciia
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Joined: Wed Nov 16, 2016 3:04 am

Gibbs Free energy

How do you know what temperature to use for delta G when it’s not given in the question?

Cynthia Aragon 1B
Posts: 47
Joined: Mon Apr 09, 2018 1:38 pm

Re: Gibbs Free energy

The standard temperature used is 298k.

Desiree1G
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Re: Gibbs Free energy

Standard temperature is 25 degrees celcius, however for Gibbs free energy we always use Kelvin so it is 273+25 which is 298 K

Ethan Baurle 1A
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Joined: Fri Sep 28, 2018 12:19 am

Re: Gibbs Free energy

Sometimes, if given enough values, you may have the use the equation PV=nRT to solve for temperature.

Henry Dudley 1G
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Joined: Fri Sep 28, 2018 12:16 am

Re: Gibbs Free energy

If the temperature is not given try the ideal gas law, however, if that isn't possible, then use k=298.

Danny Zhang 4L
Posts: 62
Joined: Fri Sep 28, 2018 12:26 am

Re: Gibbs Free energy

When it's not given, it is usually suggested to be 298K.