## Gibbs Free Energy for Molecules in their Natural States

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Clarissa Cabil 1I
Posts: 66
Joined: Fri Sep 28, 2018 12:19 am

### Gibbs Free Energy for Molecules in their Natural States

Just to clarify, for elements in their natural state (e.g. H2 (g), O2 (g), etc.), is their standard Gibbs free energy of formation equal to 0? Does this have anything to do with the standard enthalpy of formation for these elements equaling to 0?

Charles Gu 1D
Posts: 60
Joined: Fri Sep 28, 2018 12:16 am

### Re: Gibbs Free Energy for Molecules in their Natural States

Elements in their natural state have 0 Gibbs free energy.