Gibbs free energy at equilibrium

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Katherine Grillo 1B
Posts: 69
Joined: Fri Sep 28, 2018 12:28 am

Gibbs free energy at equilibrium

Why is delta G 0 at equilibrium? I don't understand conceptually why that's the case

Tiffany_Cacy_3D
Posts: 70
Joined: Fri Sep 28, 2018 12:24 am

Re: Gibbs free energy at equilibrium

Delta G is 0 at equilibrium because the forward and the backward reactions are equivalent which would mean they cancel each other out.

Miya Lopez 1I
Posts: 62
Joined: Tue Nov 14, 2017 3:00 am
Been upvoted: 1 time

Re: Gibbs free energy at equilibrium

When a reaction is at equilibrium, no more work can be done and the Gibbs free energy or delta G is zero.

Return to “Gibbs Free Energy Concepts and Calculations”

Who is online

Users browsing this forum: No registered users and 2 guests