ln(k2/k1)=(-delta H/R)(1/T2 - 1/T1)






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Emmaraf 1K
Posts: 94
Joined: Sat Oct 20, 2018 12:16 am

ln(k2/k1)=(-delta H/R)(1/T2 - 1/T1)

Postby Emmaraf 1K » Mon Feb 25, 2019 11:51 pm

We learned this equation in class but to calculate K when not at 25 degrees C yet it's not on our formula sheet. Will it be on the test and if so how would it show up/would we have to memorize it?

Shubham Rai 2C
Posts: 64
Joined: Fri Sep 28, 2018 12:27 am

Re: ln(k2/k1)=(-delta H/R)(1/T2 - 1/T1)

Postby Shubham Rai 2C » Tue Feb 26, 2019 12:02 am

This is a derived equation from the formula of delta G (standard) = -RTlnK where you solve for K for two different T value. You have to combine the two different T equations to find the equation ln(k2/k1)=(-delta H/R)(1/T2 - 1/T1). So technically it is on the equation sheet, but you can memorize it to not have to go through these steps.

Jonny Schindler 1A
Posts: 30
Joined: Fri Sep 28, 2018 12:20 am

Re: ln(k2/k1)=(-delta H/R)(1/T2 - 1/T1)

Postby Jonny Schindler 1A » Tue Feb 26, 2019 4:41 pm

Can anyone provide an example of using this equation?

Selina Bellin 2B
Posts: 62
Joined: Fri Sep 28, 2018 12:25 am

Re: ln(k2/k1)=(-delta H/R)(1/T2 - 1/T1)

Postby Selina Bellin 2B » Tue Feb 26, 2019 4:43 pm

memorize it and understand where it comes from, but i believe it's also on the test's formula page


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