## 11.15 6th Edition

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Dustin Shin 2I
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Joined: Fri Sep 28, 2018 12:26 am

### 11.15 6th Edition

I thought when Gibbs free energy was positive, the reaction is non spontaneous. If so, then why is the answer for this question saying spontaneous even though they gave a positive value for Gibbs free energy or is this just a misunderstanding on my part?

Chem_Mod
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### Re: 11.15 6th Edition

You're right in that it is nonspontaneous when producing I, but when producing I2, it is spontaneous because it is in the opposite direction.

Carissa Young 1K
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Joined: Fri Sep 28, 2018 12:17 am

### Re: 11.15 6th Edition

What does it mean if Gibbs free energy is 0 exactly?

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