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Posted: Thu Feb 28, 2019 2:32 pm
by josephyim1L
Can someone walk through this question with me:

11.17 (a) Calculate the reaction Gibbs free energy of N2(g) ->3 H2(g) S 2 NH3(g) when the partial pressures of N2, H2, and NH3 are 4.2 bar, 1.8 bar, and 21 bar, respectively, and the temperature is 400. K. For this reaction, K = 41 at 400. K. (b) Indicate whether this reaction mixture is likely to form reactants, is likely to form products, or is at equilibrium.

Re: 11.17

Posted: Thu Feb 28, 2019 6:22 pm
by Chem_Mod
The problem gives you information about the K value and concentrations that can be used to get the Q value. ΔG = ΔG0 + R*T*ln(Q) can then be used to calculate the ΔG.

Re: 11.17

Posted: Thu Feb 28, 2019 6:34 pm
by Danny Zhang 4L
Going further with the directions that is provided, you can calculate ΔG^(o) with the K given to you through -RTln(K).

Re: 11.17

Posted: Thu Feb 28, 2019 6:56 pm
by Carissa Young 1K
Since the reaction is not at equilibrium, you need to use deltaG=deltaGo + RTlnQ which can be further written as deltaG=-RTlnK + RTlnQ