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I am also confused. I understand that delta H would be negative if you are freezing and thus losing heat, but wouldn't delta S also be negative if you are losing entropy going from a liquid to a solid? Thanks in advance!
I'm not completely sure. But I assumed that because it is precipitation, the water is going from liquid to solid state. Because the freezing point of liquid water was 0 degrees C, I assumed that the precipitation would be spontaneous as the surrounding temperature was -10 degrees C, which is less than the freezing point.
I don't think this is the way to answer the question but something that helps me conceptualize it is that heat diffuses out. If a sample of water is in a 10 degree Celsius space, heat leaves the sample and the bonds form spontaneously because of the conditions it is in.
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