gibbs free energy of formation

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

705121606
Posts: 68
Joined: Wed Sep 18, 2019 12:17 am

gibbs free energy of formation

How come a negative value of gibbs free energy is more stable compared to a positive value?

Bella Townsend
Posts: 50
Joined: Wed Feb 20, 2019 12:18 am

Re: gibbs free energy of formation

Gibbs free energy with a negative value, is a spontaneous reaction that produces more stable reactants compared to that of a non spontaneous reaction.

At a substances lowest energy state is its most stable configuration.

charleejohnson1L
Posts: 99
Joined: Fri Aug 30, 2019 12:17 am

Re: gibbs free energy of formation

Like said above, Gibbs Free Energy is more stable when negative due to the spontaneity of the reaction. If the reaction isn't favorable/ spontaneous, then forcing it to happen may not result in the most stable products. I hope this helps! :)

Andres Merlos 2L
Posts: 46
Joined: Wed Sep 18, 2019 12:17 am

Re: gibbs free energy of formation

If Gibbs Free Energy is negative, it is more stable because it refers to spontaneity of a reaction. Spontaneous reactions tend to yield more stable products as they are not "forced" to undergo a reaction, in contrast to a non-spontaneous reaction.