## GFE dividing by temp

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

JosephineF
Posts: 49
Joined: Wed Sep 18, 2019 12:17 am

### GFE dividing by temp

Does anyone have a deeper explanation for why we would divide ΔG by T for the equation -ΔG/T= -ΔH/T + ΔSsys? In lecture I didn't understand what the purpose was for doing this.

CynthiaLy4F
Posts: 103
Joined: Sat Jul 20, 2019 12:16 am

### Re: GFE dividing by temp

I believe the purpose for that was to manipulate the equation to show how -deltaG/T of the system is equal to deltaS of the universe, which means that in order for a spontaneous process to occur where deltaS is positive, then deltaG must be negative.

Angela Patel 2J
Posts: 110
Joined: Sat Aug 24, 2019 12:17 am

### Re: GFE dividing by temp

Because - delta H / T is the change in entropy of the surroundings (discussed earlier in lecture today) and this makes the equation easier to simplify into something that only has one variable. This way we can define spontaneity of a process in terms of only gibbs free energy.

Rebekah Alfred 1J
Posts: 102
Joined: Thu Jul 11, 2019 12:15 am
Been upvoted: 1 time

### Re: GFE dividing by temp

We know if it is a spontaneous process if the delta S of the universe is positive, which means that the delta G of the system must be negative.