## Gibbs Free Energy

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

504999222
Posts: 25
Joined: Tue Nov 13, 2018 12:18 am

### Gibbs Free Energy

Why is Delta U a state function when Q+ W are both path functions?

How can two-path functions equal a state function?

JonathanS 1H
Posts: 101
Joined: Thu Jul 11, 2019 12:17 am

### Re: Gibbs Free Energy

With U, we only consider it at specific points in time rather than considering how specifically the internal energy of a system has changed.

Jared_Yuge
Posts: 100
Joined: Sat Aug 17, 2019 12:17 am

### Re: Gibbs Free Energy

Because heat and work are related to delta U directly as the two different methods showing how energy is transferred in and out of the system. Say delta U was +2kJ, the q and w could be any combination of energy values as long as the sum is +2kJ.

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