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To add on, you can figure out when ∆G = 0 by using the mathematical relationships between ∆G˚= - RTlnK and ∆G = ∆G˚ + RTlnQ. We know that at equilibrium Q=K. If we substitute ∆G˚out, then ∆G = RTlnQ - RTlnK, thus ∆G = RTlnQ - RTlnK = RTlnK - RTlnK = 0 when the reaction is at equilibrium.
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