Go=0






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EMurphy_2L
Posts: 128
Joined: Sat Sep 07, 2019 12:16 am

Go=0

Postby EMurphy_2L » Tue Feb 11, 2020 12:01 am

when does G*=0

Wendy 1E
Posts: 111
Joined: Sat Aug 17, 2019 12:17 am
Been upvoted: 2 times

Re: Go=0

Postby Wendy 1E » Tue Feb 11, 2020 12:05 am

In lecture today we learned that ΔG is zero at a reaction's boiling point.

JesseAuLec1Dis1G
Posts: 52
Joined: Mon Jun 17, 2019 7:23 am

Re: Go=0

Postby JesseAuLec1Dis1G » Tue Feb 11, 2020 12:05 am

Gibb's free energy is at zero when the reaction is at equilibrium.

Abigail Sanders 1E
Posts: 112
Joined: Wed Sep 11, 2019 12:16 am

Re: Go=0

Postby Abigail Sanders 1E » Tue Feb 11, 2020 12:21 am

To clarify the last two responses, Gibbs Free energy is 0 both at the boiling point and when the reaction is at equilibrium.

alex_4l
Posts: 109
Joined: Thu Sep 26, 2019 12:18 am

Re: Go=0

Postby alex_4l » Tue Feb 11, 2020 1:28 am

G = 0 when the rate of forward reaction equals the rate of the reverse reaction (equilibrium)

preyasikumar_2L
Posts: 101
Joined: Fri Aug 09, 2019 12:17 am

Re: Go=0

Postby preyasikumar_2L » Tue Feb 11, 2020 2:54 am

ΔG = 0 means that the system is at equilibrium - the forward and reverse reactions are occurring at the same rate at the same time.

Eva Zhao 4I
Posts: 101
Joined: Sun Sep 29, 2019 12:16 am

Re: Go=0

Postby Eva Zhao 4I » Fri Feb 28, 2020 8:14 am

∆G˚=0 when products and reactants are in their standard state and K=1. Note that this is not common.

Justin Quan 4I
Posts: 104
Joined: Sat Sep 14, 2019 12:17 am

Re: Go=0

Postby Justin Quan 4I » Fri Feb 28, 2020 8:47 am

To add on, you can figure out when ∆G = 0 by using the mathematical relationships between ∆G˚= - RTlnK and ∆G = ∆G˚ + RTlnQ. We know that at equilibrium Q=K. If we substitute ∆G˚out, then ∆G = RTlnQ - RTlnK, thus ∆G = RTlnQ - RTlnK = RTlnK - RTlnK = 0 when the reaction is at equilibrium.


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