∆G, ∆H, ∆S

[Donna Nguyen 2L]

What's the relationship between ∆G, ∆H, and ∆S? I know that the Gibbs Free Energy equation is ∆G = ∆H - T∆S, but I'm not sure how exactly it all fits together.

[Ashley Tran 2I]

Based on where we are in class, this has been the only relationship established. You can also think of how relative the values of ∆H and ∆S make ∆G negative at which temperatures to determine whether a reaction is spontaneous.

[Kassidy Ford 1I]

^^ as they said above, in order for a spontaneous reaction to occur, deltaG must be negative. This means that the value for T*deltaS must be greater than the change in enthalpy. For an endothermic reaction where enthalpy is a positive number this is often not true except at very high temperatures.

[Megan Kirschner]

They relate because they can tell you lots of things about if a reaction will occur spontaneously and if it's favorable. It is expected that how this could be presented on a test would be if you were given all or some of these terms and asked to deduce overall conclusions about the system.

[Bryan Chen 1H]

basically, deltaG depends on deltaH and deltaS to be a spontaneous(-) or nonspontaneous(+) rxn. Since it is a new topic i dont think we need to know much more than that

[Eva Zhao 4I]

Here's a table that relates the three fairly well, with respect to T in order to determine spontaneity:

[Justin Quan 4I]

To add on, ∆G = ∆H - T∆S is very useful for predicting if a given reaction is spontaneous or non-spontaneous. When ∆G=0 the system is at equilibrium. When ∆G is negative, the forward reaction is spontaneous. When ∆G is positive, the reverse reaction is spontaneous. The sign of ∆G depends on the enthalpy, entropy, and temperature; Its relationship is modeled by the equation ∆G = ∆H - T∆S.