## Delta G and spontaneity

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Sara Richmond 2K
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Joined: Fri Aug 30, 2019 12:16 am

### Delta G and spontaneity

I know a negative delta g means the reaction is spontaneous. A positive delate g means the reaction is not spontaneous. But does a negative delta g means the reaction favors products and a positive delta g means the reaction favors reactants.

805394719
Posts: 104
Joined: Wed Sep 11, 2019 12:16 am

### Re: Delta G and spontaneity

If you have a delta G that is negative which means that the reaction is spontaneous, then the reaction does not need energy to proceed. In other words, it will occur on its own without any external intervention. Because this reaction occurs spontaneously without the input of energy, this means that the products are more stable and thus favored than the reactants. So, this means that if you have a spontaneous reaction, the products are favored, whereas if you have a non spontaneous reaction where the delta G is positive, the reaction will not occur unless energy supplied, this means that the energy of the products is greater than the reactants and thus most likely less stable. The forward reaction will not be favorable in that case.

Tyler Angtuaco 1G
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Joined: Wed Sep 11, 2019 12:16 am

### Re: Delta G and spontaneity

Yes since a spontaneous reaction is one that will likely occur on its own without intervention. Thus, products will likely form since the reaction is likely to proceed.

Anika Chakrabarti 1A
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Joined: Sat Aug 24, 2019 12:17 am

### Re: Delta G and spontaneity

Yes because a spontaneous reaction means that the reaction is more likely to proceed and more products are likely to form. If a reaction is not spontaneous, the reactants are unlikely to form products, so the reverse reaction is favored.

Nuoya Jiang
Posts: 99
Joined: Sat Sep 14, 2019 12:17 am

### Re: Delta G and spontaneity

Yes, because when delta G is negative, it tends to release energy when proceeding to the products, and vice versa.

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