## Delta G

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

MaryBanh_2K
Posts: 101
Joined: Wed Sep 18, 2019 12:21 am

### Delta G

Why do we solve for delta G of the reaction using the delta G with the degree sign? I know that the degree sign indicates that the reaction is at standard temperature and pressure but what is the significance of this?

Ariel Davydov 1C
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### Re: Delta G

The purpose of the degree sign is to indicate that the relationship between enthalpy, entropy, and temperature in regards to spontaneity is deltaG = deltaH -T*deltaS only at standard conditions.

Posts: 52
Joined: Thu Jul 11, 2019 12:16 am

### Re: Delta G

The Delta G with the degree sign is the one being calculated because this is under standard conditions for the reaction and correlates to a standard enthalpy and entropy and is calculated that way.

Zoe Gleason 4F
Posts: 51
Joined: Tue Jul 23, 2019 12:15 am

### Re: Delta G

It means that it is under standard conditions. In calculating ΔG, if you wanted to calculate the standard form, you would have to use other values that are also in their standard form.

Ruth Glauber 1C
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### Re: Delta G

Lauren Tanaka 1A
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### Re: Delta G

The naught sign means that the conditions are under STP or standard temperature and pressure. If the delta G has the naught symbol then so does the delta S and H.

Kristina Rizo 2K
Posts: 105
Joined: Wed Sep 18, 2019 12:19 am

### Re: Delta G

Lauren Tanaka 1A wrote:The naught sign means that the conditions are under STP or standard temperature and pressure. If the delta G has the naught symbol then so does the delta S and H.

STP is 1 atm and 273.15K right ?