5G.15

[ayushibanerjee06]

For 5G.15, (a) Calculate the reaction Gibbs free energy of N2(g) 1 3 H2(g) S 2 NH3(g) when the partial pressures of N2, H2, and NH3 are 4.2 bar, 1.8 bar, and 21 bar, respectively, and the temperature is 400. K. For this reaction, K 5 41 at 400. K. (b) Indicate whether this reaction mixture is likely to form reactants, is likely to form products, or is at equilibrium, I keep getting my answer to be -23.29 kJ even though the answer is -27 kJ/mol. My standard GFE is -32.9 KJ/mol (times 3), R is 8.314, T is 400 K, and Q is 18.004.

[Selena Yu 1H]

For 5G.15, for the standard GFE I got -12.35 kJ and for my final answer, I actually got -2.7 kJ/mol instead of -27 kJ/mol

[ayushibanerjee06]

For 5G.15, for the standard GFE I got -12.35 kJ and for my final answer, I actually got -2.7 kJ/mol instead of -27 kJ/mol

How did you get -12.35 kJ? I used the one for NH3 in the back of the book that was -32.9 kJ/mol since the standard GFE for the reactants are zero.

[Hiba Alnajjar_2C]

For 5G.15, for the standard GFE I got -12.35 kJ and for my final answer, I actually got -2.7 kJ/mol instead of -27 kJ/mol

I also got -2.7 kJ/mol, did you happen to figure out what went wrong? Thank you!!

[Selena Yu 1H]

For 5G.15, for the standard GFE I got -12.35 kJ and for my final answer, I actually got -2.7 kJ/mol instead of -27 kJ/mol

I also got -2.7 kJ/mol, did you happen to figure out what went wrong? Thank you!!

I'm not sure I think the book just made an error but I checked with other people and they also got -2.7 kJ/mol. Hope that helps!

[Selena Yu 1H]

For 5G.15, for the standard GFE I got -12.35 kJ and for my final answer, I actually got -2.7 kJ/mol instead of -27 kJ/mol

How did you get -12.35 kJ? I used the one for NH3 in the back of the book that was -32.9 kJ/mol since the standard GFE for the reactants are zero.

For this question, you also use the equation deltaG = -RTlnK to find the standard GFE because you were given K and values to find Q.