Equilibrium






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Vanessa Rojas 4F
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Equilibrium

Postby Vanessa Rojas 4F » Sat Feb 15, 2020 9:31 pm

Why is delta G naught 0 at equilibrium?

Daria Azizad 1K
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Joined: Thu Jul 25, 2019 12:15 am

Re: Equilibrium

Postby Daria Azizad 1K » Sat Feb 15, 2020 9:35 pm

At equilibrium, the system does not have a preference for the forward or reverse rxn, so neither would spontaneously occur

alicechien_4F
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Re: Equilibrium

Postby alicechien_4F » Sat Feb 15, 2020 9:38 pm

At equilibrium, the forward and reverse reactions occur at the same rate. This means that neither reaction is favored, and so neither reaction is spontaneous.

Nicholas_Gladkov_2J
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Re: Equilibrium

Postby Nicholas_Gladkov_2J » Sat Feb 15, 2020 10:13 pm

Vanessa Rojas 4F wrote:Why is delta G naught 0 at equilibrium?


When delta G is negative, the reaction is spontaneous.
When delta G is positive it is not spontaneous, but you could think of the reverse reaction to be favored.

So, when delta G is negative, there is not a preference to proceed to products, nor is there a favoring of the reverse reaction, thus the reaction is at equilibrium.

Esha Chawla 2E
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Re: Equilibrium

Postby Esha Chawla 2E » Sat Feb 15, 2020 10:19 pm

Vanessa Rojas 4F wrote:Why is delta G naught 0 at equilibrium?


By definition, equilibrium is when the forward and backward reaction rates are equal. If delta G naught is 0, this means that the thermodynamic potential is the same of both the reactants and products. As such, there is no favorable direction the reaction must proceed in (as both reactants and products have equal thermodynamic ability), which means that the reaction is in equilibrium.

ayushibanerjee06
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Re: Equilibrium

Postby ayushibanerjee06 » Sat Feb 15, 2020 10:50 pm

if you use the deltag=-nrtlnK equation, it will equal zero because, at equilibrium, K=1 and ln(1)=0.

BritneyP- 2c
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Re: Equilibrium

Postby BritneyP- 2c » Sat Feb 15, 2020 11:03 pm

At equilibrium, the forward and reverse reactions are at the same rate. This means that no reaction is favored as G is not positive or negative, meaning that the reaction is not spontaneous

WesleyWu_1C
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Re: Equilibrium

Postby WesleyWu_1C » Sun Feb 16, 2020 2:08 am

So when a reaction is at equilibrium, delta G is equal to 0. The only way delta G naught is also equal to zero is if K = 1.

Andres Merlos 2L
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Re: Equilibrium

Postby Andres Merlos 2L » Sun Feb 16, 2020 3:27 pm

Neither reverse nor forward reaction is favored at equilibrium, so at delta G naught 0, the reaction is neither spontaneous nor non-spontaneous. This would mean neither reaction is favored, so it would be at equilibrium.

Vinita Saxena 2I
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Re: Equilibrium

Postby Vinita Saxena 2I » Sun Feb 16, 2020 5:43 pm

When delta G is 0 there is no preference to products or reactants, so it is at equilibrium.

Daria MacAuslan 1H
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Re: Equilibrium

Postby Daria MacAuslan 1H » Sun Feb 16, 2020 5:54 pm

At equilibrium, we know that both the forward and reverse reactions are occurring at roughly the same rate, and with roughly the same favorability. This means that neither one is specifically favored or spontaneous, so delta g is 0

rohun2H
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Re: Equilibrium

Postby rohun2H » Sun Feb 16, 2020 8:37 pm

Neither reaction is favored at equilibrium.

205389184
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Joined: Sat Sep 07, 2019 12:18 am

Re: Equilibrium

Postby 205389184 » Sun Feb 16, 2020 10:06 pm

Since both the forward and reverse reactions are occurring at the same rate in equilibrium, delta G naught would be equal to zero

Matthew Tsai 2H
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Joined: Wed Sep 18, 2019 12:20 am

Re: Equilibrium

Postby Matthew Tsai 2H » Tue Feb 18, 2020 12:12 am

Delta G is zero at equilibrium because the concentrations of products and reactants are not changing and neither the forward nor reverse reaction is favored; given that the system isn't doing work, there is nothing that would cause a change in free energy of the system.

Viviana Velasquez
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Re: Equilibrium

Postby Viviana Velasquez » Wed Feb 19, 2020 12:10 pm

Since K=1 at equilibrium and the equation is RTln(K), ln(1)=0 making Delta G=0

Jessica Kwek 4F
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Re: Equilibrium

Postby Jessica Kwek 4F » Wed Feb 19, 2020 4:38 pm

At equilibrium, delta G would be 0 since the reactants and products are occurring at the same rate, which means that the reaction favors neither side.


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