## Equilibrium [ENDORSED]

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

ng1D
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### Equilibrium

When a reaction of a system is at equilibrium, why is there no work done by the reaction?

Chem_Mod
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### Re: Equilibrium  [ENDORSED]

At equilibrium there is no net change and therefore no energy released.
I'll comment on this in class.

Posts: 102
Joined: Tue Oct 02, 2018 12:16 am

### Re: Equilibrium

Because there is no net change occurring, no total work is done. That is because the energy is in equilibrium as well.

Dan M -3E
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Joined: Wed Sep 18, 2019 12:19 am

### Re: Equilibrium

At equilibrium, the energy coming in and being released by work are equal. Basically, the net work being done on and by the system is 0 because the energy of the system is at eq.