delta vs. delta naught

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Rachel Yu 1G
Posts: 113
Joined: Fri Aug 09, 2019 12:15 am

delta vs. delta naught

What is the difference between delta G, H, and S versus delta G naught, H naught, and S naught?

Vicki Liu 2L
Posts: 101
Joined: Sat Aug 24, 2019 12:15 am

Re: delta vs. delta naught

The naught simply indicates that the values of G, H, and S are measured at STP conditions (1 atm and 273 K).

Aman Sankineni 2L
Posts: 103
Joined: Fri Aug 30, 2019 12:17 am

Re: delta vs. delta naught

The difference between the two is that delta G naught is at standard conditions. The reason Professor Lavelle emphasized it is because delta G naught is always the same because it is referring to when the reactants/products are at standard temperature/pressure. As the rxn goes towards equilibrium, delta G (without the naught) changes because the rxn is proceeding. So as the chemical rxn approaches equilibrium, delta G (without the naught) approaches zero. However, delta G naught remains the same because it is still referring to when the rxn is at standard conditions. I hope that helped!

Kallista McCarty 1C
Posts: 212
Joined: Wed Sep 18, 2019 12:18 am

Re: delta vs. delta naught

The naught symbolizes standard temperature and pressure (STP)