5G.17

[Junwei Sun 4I]

The question asks to draw a graph that depicts the reaction in question 5G.13 which is I2(g) --> 2I(g) at 1200.K (K=6.8) when the partial pressure of I2 and I are 0.13 bar and 0.98 bar respectively. The answer key gives this graph but I still don't quite get what it means. Could someone please explain?

[Ryan Narisma 4G]

Hi Junwei Sun 4I! To answer your question, because the reaction quotient value is greater than the value of K at this temperature, the reaction will proceed to form more reactants (I₂ gas). The graph is depicting this instance. As time progresses, the reaction will start to form more I₂, hence the increase in the partial pressure of I₂. However, in doing so, the reaction must use up I (g) and this is depicted with the partial pressure of I (g) decreasing. Then when the reaction reaches equilibrium the partial pressures of each species remain unchanged, hence the leveling off of the partial pressures of each species after reaching a certain time. I hope this helps!

[Junwei Sun 4I]

Hi Junwei Sun 4I! To answer your question, because the reaction quotient value is greater than the value of K at this temperature, the reaction will proceed to form more reactants (I₂ gas). The graph is depicting this instance. As time progresses, the reaction will start to form more I₂, hence the increase in the partial pressure of I₂. However, in doing so, the reaction must use up I (g) and this is depicted with the partial pressure of I (g) decreasing. Then when the reaction reaches equilibrium the partial pressures of each species remain unchanged, hence the leveling off of the partial pressures of each species after reaching a certain time. I hope this helps!

Thank you!