5G 17

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5G 17

Postby LBacker_2E » Wed Feb 19, 2020 5:38 pm

I am confused on why the answer in the book said that the I was the reactant and the I2 was the product in the graph, when the equation we were given said the reverse. Is this just a typo, or can someone explain why it should be this way?

Daniel Honeychurch1C
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Re: 5G 17

Postby Daniel Honeychurch1C » Wed Feb 19, 2020 10:18 pm

I believe that it is a typo, because the reaction in 5G.13 (which is what you graph in 5G.17) is I2 (aq) --> 2I (g).

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