## 5J.11b

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Eileen Si 1G
Posts: 120
Joined: Fri Aug 30, 2019 12:17 am

### 5J.11b

Is X2(g) = 2X(g) where X is a halogen an endothermic or exothermic reaction, and why? Wouldn't it be an exothermic reaction because the bond between an X2 molecule is broken to become 2 separate X atoms?

Angus Wu_4G
Posts: 102
Joined: Fri Aug 02, 2019 12:15 am

### Re: 5J.11b

I'm not too sure, but I think it depends on the temperature at which this reaction is occurring. In general though, I would imagine this reaction is endothermic because it takes a lot of energy to break the bonds, and while you do release energy when the bond is broken, I think overall it takes more energy to breakup the bond than the energy you get out of it.