## Midterm 6B

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

705121606
Posts: 68
Joined: Wed Sep 18, 2019 12:17 am

### Midterm 6B

It asks for which process with delta H and delta G be expected to be most similar? I narrowed it down to either a or b during the test but then I got confused on the difference between them. The only thing I noticed was that option a was all in the solid state whereas option b had many different phases. Can someone explain why option a was correct in this problem and why options b,c,d would be incorrect

Amanda Lin 2I
Posts: 101
Joined: Sat Aug 17, 2019 12:15 am

### Re: Midterm 6B

ΔG° = ΔH° - TΔS°
ΔH° and ΔG° would be the most similar when ΔS° is closest to 0. Going from a solid to another solid would have the smallest change in entropy, so A is the correct answer.

Julie_Reyes1B
Posts: 105
Joined: Sat Jul 20, 2019 12:16 am

### Re: Midterm 6B

This is the way I did it, but I'm not quite sure if it is correct. So I used the equation ΔG°= ΔH- TΔS°. So for G and H to be equal, TΔS°=0. B, C, and D would be wrong because there is a pretty clear change in entropy for each one.

Justin Seok 2A
Posts: 104
Joined: Sat Aug 24, 2019 12:15 am

### Re: Midterm 6B

Essentially, this problem is asking for which equation would cause the least entropy so that G and H are similar. Entropy changes quite significantly when phases change, so the equation with the least entropy change would be the one with the solids on both sides.