## 5G.17

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Ellis Song 4I
Posts: 102
Joined: Thu Jul 11, 2019 12:17 am

### 5G.17

This question asks us to depict the progress of the reaction I2(g) -> 2I(g) graphically. Can someone explain how to do this?

Goyama_2A
Posts: 107
Joined: Sat Aug 24, 2019 12:17 am

### Re: 5G.17

To do this, you need to look at the relative rates of the product and reactant. You can see that I is being formed doubly as fast as I2 is being used up, due to the 1:2 ratio. To graph this, you just need to demonstrate this relationship using a graph of time on the x axis and concentration being on the y axis.

005162520
Posts: 101
Joined: Tue Sep 24, 2019 12:17 am

### Re: 5G.17

how would we show the ratio on the graph ?