## Reaction Free Energy

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Haley Dveirin 1E
Posts: 101
Joined: Sat Jul 20, 2019 12:17 am

### Reaction Free Energy

One of the bullets on the second pager of the thermodynamics outline says "Understand why reaction free energy depends on pressure and the equilibrium constant." Can someone explain this?

Sjeffrey_1C
Posts: 108
Joined: Wed Feb 20, 2019 12:17 am

### Re: Reaction Free Energy

For the equilibrium constant part, this is evident in the equation delta G naught = -RTlnK. I'm not sure how pressure plays a part. Maybe because the equilibrium constant can be calculated with the partial pressures of the products and reactants.

Anish Natarajan 4G
Posts: 51
Joined: Thu Jul 25, 2019 12:16 am

### Re: Reaction Free Energy

Depending on the pressure, the reaction can shift to favor either the products or reactants and the value of K also dictates whether or not a reaction is product favored (large K) or reactant favored (small K)