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Does the standard delta G (with the degree sign) mean the reaction is at equilibrium? Can you also find standard delta G (with the degree sign) with the Q value or does it only with the equilibrium constant, K?
If you are provided delta G, R, T, and Q, then you can find standard delta G. However, if you are given K, it means that the reaction has reached equilibrium and delta G = 0, therefore you would get the equation standard delta G = -RTlnK.
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