self-test explanation

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Payton Kammerer 2B
Posts: 49
Joined: Tue May 01, 2018 3:00 am

self-test explanation

Postby Payton Kammerer 2B » Sat Mar 14, 2020 6:25 pm

Self-test 4J.1A Can a nonspontaneous process with a negative DS become spontaneous if the temperature is increased (assuming that DH and DS are both independent of temperature)? [Answer: No]

Why is the answer no? I thought it would be yes since T is multiplied by DS

Indy Bui 1l
Posts: 99
Joined: Sat Sep 07, 2019 12:19 am

Re: self-test explanation

Postby Indy Bui 1l » Sat Mar 14, 2020 6:35 pm

I think it is because delta S is negative. So in the equation DeltaG=DeltaH-TDeltaS, delta S being negative would make delta G positive, increasing T would just make it more positive, because delta G is positive when it is non-spontaneous. (-T*-deltaS is going to equal a positive number)

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