## self-test explanation

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

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Payton Kammerer 2B
Posts: 49
Joined: Tue May 01, 2018 3:00 am

### self-test explanation

Self-test 4J.1A Can a nonspontaneous process with a negative DS become spontaneous if the temperature is increased (assuming that DH and DS are both independent of temperature)? [Answer: No]

Why is the answer no? I thought it would be yes since T is multiplied by DS

Indy Bui 1l
Posts: 99
Joined: Sat Sep 07, 2019 12:19 am

### Re: self-test explanation

I think it is because delta S is negative. So in the equation DeltaG=DeltaH-TDeltaS, delta S being negative would make delta G positive, increasing T would just make it more positive, because delta G is positive when it is non-spontaneous. (-T*-deltaS is going to equal a positive number)

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