## Ppt Question

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Jessica Chen 2C
Posts: 103
Joined: Thu Jul 11, 2019 12:17 am

### Ppt Question

For the question on slide 5 of the final review PowerPoint, why do we only use the delta G for PCl5 and PCl3 when calculating the delta G of the reaction?

Katie Kyan 2K
Posts: 106
Joined: Fri Aug 09, 2019 12:16 am
Been upvoted: 1 time

### Re: Ppt Question

This is because the standard gibbs free energy for Cl2 is 0 as diatomic molecules are already in their standard state. Thus when calculating the delta G of the reaction we exclude the delta G for Cl2 since it is 0.

Frank He 4G
Posts: 50
Joined: Tue Nov 12, 2019 12:19 am

### Re: Ppt Question

I think it might be because the gibbs free energy of formation for Cl2 is 0, since it's already in its most stable form.