## Midterm 6B

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Maya Gollamudi 1G
Posts: 100
Joined: Thu Jul 25, 2019 12:15 am

### Midterm 6B

Q6B. For which process will ∆Ho and ∆Go be expected to be most similar? Ans ____A (3pt)
(A) 2Al(s) + Fe2O3(s) → 2Fe(s) + Al2O3(s)
(B) 2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)
(C) 2NO2(g) → N2O4(g)
(D) 2H2(g) + O2(g) → 2H2O(g)

Do you have to calculate both delta H0 and delta G0 to determine the answer to this question?

Jessa Maheras 4F
Posts: 121
Joined: Fri Aug 02, 2019 12:16 am

### Re: Midterm 6B

For this one, I used conceptual reasoning that because A is the only rxn with all reactants and products as solids, it will have very small changes in S, therefore dG and dH should be similar. :)

saigorijavolu2k
Posts: 108
Joined: Sat Sep 28, 2019 12:15 am

### Re: Midterm 6B

I chose a because the states of the reactants and products were similar thus an entropy change will not be too large, which implies a similar delta H and delta G

Alan Cornejo 1a
Posts: 98
Joined: Fri Aug 30, 2019 12:15 am

### Re: Midterm 6B

For this question since the answer choice a has reactants and products all as solids in the same phase, there will be almost not entropy change.