Spontaneous as Written
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Re: Spontaneous as Written
If the delta G of a reaction is negative, then that reaction will be spontaneous under those conditions. I'm not sure what you mean by spontaneous as written, but I hope this answers your question!
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Re: Spontaneous as Written
That is correct. It is also good to understand that if ΔSunivis positive, then ΔGrxn is negative. Therefore, the reaction would be spontaneous.
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Re: Spontaneous as Written
Yes, this could be due to two reasons, the change in entropy being positive (which makes sense since the more chaos or entropy you get, the more spontaneously it could have happened since that's how things naturally work) or due to the enthalpy change being more negative (so less order or enthalpy occurs).
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Re: Spontaneous as Written
The negative value of ΔG° indicates that the reaction is spontaneous as written.
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Re: Spontaneous as Written
wait, can someone please explain what exactly is meant when we say "as written"? has that phrasing ever been mentioned in lecture, if so when/which one?
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Re: Spontaneous as Written
Yes, that's correct. If delta G is negative, then the reaction is always considered spontaneous.
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Re: Spontaneous as Written
What everyone said above is correct, but make sure you look at ΔG° vs ΔG. For a reaction to be spontaneous, only its ΔG has to be negative, not its ΔG° (which is the ΔG for that reaction at standard conditions). This is relevant when you're looking at reactions that aren't taking place under standard conditions. If you need to calculate the ΔG from the ΔG°, use the equation ΔG = ΔG° + RTlnQ.
Re: Spontaneous as Written
Yes, that is correct. A negative delta G means that the reaction is spontaneous and comes from the fact that temperature*deltaS (entropy) is higher than deltaH (enthalpy). I would also like to emphasize the comment that Megan posted about the difference between deltaG0 (which is a set value that depends on what the reaction that we're looking at is at standard temperature and pressure condition) and deltaG.
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