G° vs G

[Rayna Irving 2C]

Quick question, how is G°different from just G?

[Chanel Mao 3D]

G° is just G in standard temperature and pressure (298K and 1atm)

[Gwen Casillan 3E]

Gº is under standard conditions, whereas G isn't.

[Alison Perkins 2B]

ΔG = ΔG° + -RTln(Q)

The degrees on the delta G means that this is the standardized value.

[Aanya Tanti 3C]

G° means under standard conditions (1 atm and 273 K) while G does not specify any conditions.

[Jerry_T]

G° is simply the free energy at standard temperature and pressure, defined as 1 bar (or 1 atm) and 298K.

[705383815]

The difference is implied in the equation. Adding RTln(Q) to the one with the degree sign accounts for the difference. It probably involves temperature and concentrations.

[Ken_Cheng_2A]

The formula ΔG = ΔG° + -RTln(Q) lets you calculate ΔG from ΔG° because it accounts for deviations from standard conditions, and I guess you could theoretically go the other way around if you're given ΔG instead of ΔG° to start with.

[Jack_Pearce_2H]

G° is just G but at STP (1atm and 298K). G is usually helpful though in the sense that it can be used in lab settings to determine the more "normal" free energy of the reaction.

[Katelyn_Ortega_1D]

G° Is at standard temperature (which means 1 atm and 298 k)

[DavidTabib 3H]

When it is G°, the conditions are standard (1 atm and 298 K)

[Meghan Krushena 2E]

Dr. Lavelle's lecture slides stated that when ° is used it is referring to the state in standard conditions, so G is not at standard conditions with 1atm and 298K and G° is.

[Michael Cardenas 3B]

G° is G at standard conditions, so 298 K and 1 atm, and G is not at standard conditions.

[Diana Aguilar 3H]

G°is under standard conditions (298 K and 1 atm) and G is not.

[Bhuvan Kommineni 3L]

G0 is G at STP conditions. Small difference!

[Nicoli Peiris 1B]

G with the little degree above is under standard conditions.

[reyvalui_3g]

G° is under standard conditions, 298K and 1 atm.

[MCalcagnie_ 1D]

G° is just at standard conditions (pressure at 1 atm and temperature at 298K), whereas G can be at any temperature and pressure.

[Karen Zheng_2K]

The little degree symbol just stands for G at standard condition.

[America Alvarado]

In addition to this, a UA said you would use the G° equation when the reaction you're working with is at equilibrium and the equation for G when it is not since G is the difference between gibbs free energy of products and reactants at any point.

[KhanTran3K]

the delta G(0) value is just the delta G value but at standard conditions for a certain system. With this, there are different equations that we can use to relate these values. We can relate the delta G(0) value to a system at equilibrium, while we can use the delta G value in the equation, not at equilibrium (delta G = delta G(0) + RTlnQ

[jessicasilverstein1F]

G is not under standard conditions, whereas Gº is

[Tiao Tan 3C]

∆Gº is the gibbs free energy under standard conditions 298K and 1atm. ∆G is not under standard conditions and can vary.

[Gian Boco 2G]

G knot is under standard conditions

[Susan Chamling 1F]

G is not under standard conditions so the question may provide more information in this regard. On the other hand, Gº is under standard conditions (298 K and 1 atm), so we can typically assume these conditions.

[DPatel_2L]

G° is under standard conditions.

[Susanna Givan 2B]

Why is important to differentiate G from G naught? Does it affect enthalpy or entropy differently?

[Hannah Alltucker 3L]

Why is important to differentiate G from G naught? Does it affect enthalpy or entropy differently?

I think it's important because G naught will always be the same for that reaction, since everything is in standard pressure and temperature, but for normal delta G this isn't the case, so we can't just assume each reaction will be the same.

[austin-3b]

Delta G naught is standard conditions. Delta G is at any point; if equal to delta G naught, it's at equilibrium.

[tholz11]

I think of it like K and Q - G knott will be under standard conditions while G will be at adjusted conditions.

[Sara Dolmo 2J]

G knot means it is in standard conditions and regular G is not