For the lecture example about partial pressures:
How come we don't also include the Cl2, when calculating the gibbs free energy of the reaction?
Lecture Example
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Re: Lecture Example
Hi! Technically you can include the Gibbs free energy of formation of the Cl2, but it will just be 0! Cl2 is the standard state of Cl, so its Gibbs free energy of formation = 0. Hope this helps! :)
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Re: Lecture Example
because Cl2 is just an element, its gibbs free energy is 0. This means that while you can include it, it doesn't impact the calculations.
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Re: Lecture Example
I think that the CL2 is in its elemental state which means that it does need to be included because it does not have G. It is in its elemental state/
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