## Ka vs K

$\ln K = -\frac{\Delta H^{\circ}}{RT} + \frac{\Delta S^{\circ}}{R}$

Simrina Desar Dis 1H
Posts: 49
Joined: Fri Sep 29, 2017 7:04 am

### Ka vs K

How is Ka different from K and how would we consider the difference when solving equations for the equilibrium constant?

Lindsay H 2B
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Joined: Fri Sep 29, 2017 7:07 am
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### Re: Ka vs K

Ka is the equilibrium constant specifically for the dissociation of an acid. This means that if Ka is used, it means one reactant has to be an acid

Michael Downs 1L
Posts: 29
Joined: Thu Jul 13, 2017 3:00 am

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