Test #2


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Emily Ng_4C
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Joined: Fri Sep 28, 2018 12:17 am

Test #2

Postby Emily Ng_4C » Tue Mar 12, 2019 5:00 pm

the ionic dissociation of water is given by the following reaction: the deltaH for the reaction is 58 kJ/mol. The Kw for the reaction at 25 degree Celsius is 10 ^-14. Is the pH of 7 acidic or basic at 10 degree Celsius?
2H20 --> H3O+ + OH-

Why is the answer acidic?

Lily Benitez 2G
Posts: 63
Joined: Fri Sep 28, 2018 12:29 am

Re: Test #2

Postby Lily Benitez 2G » Tue Mar 12, 2019 5:22 pm

the ionic dissociation of water is given by the following reaction: the deltaH for the reaction is 58 kJ/mol. The Kw for the reaction at 25 degree Celsius is 10 ^-14. Is the pH of 7 acidic or basic at 10 degree Celsius?
2H20 --> H3O+ + OH-

You have to start by using the Van't Hoff equation which is Ln(k2/k1)=-(deltaH/R)(1/T1 - 1/T2)
You substitute everything in and find your K2. Since H3O and OH are equal concentrations you get the equation x^2 = k2. Once you find X you can take the -log and you find your ph. Then you compare 7 to the new ph value. If 7 is higher then the calculated ph it is basic, if it is lower it is acidic.

BenJohnson1H
Posts: 68
Joined: Fri Sep 28, 2018 12:17 am

Re: Test #2

Postby BenJohnson1H » Thu Mar 14, 2019 10:20 am

I still don't conceptually understand how the pH would change if H+ and OH- are at equivalent concentrations

Joonsoo Kim 4L
Posts: 61
Joined: Fri Sep 28, 2018 12:29 am

Re: Test #2

Postby Joonsoo Kim 4L » Thu Mar 14, 2019 10:14 pm

pH refers to the concentration of [H+] in solution, not necessarily the acidity of the solution. When the temperature is lowered, the Kw is also lowered (due to the van't hoff equation) so the [H+] of a neutral solution of water would also be lowered, which raises the neutral pH. If the neutral pH is raised, then a pH of 7 would be considered acidic at this new temperature.

Daisylookinland
Posts: 46
Joined: Fri Sep 28, 2018 12:28 am

Re: Test #2

Postby Daisylookinland » Fri Mar 15, 2019 9:57 pm

for my K2 value I got 2.78*10^-14

On my test I took the negative log of this value but got the answer wrong, is that the wrong approach?

Roberto Gonzalez 1L
Posts: 39
Joined: Fri Sep 28, 2018 12:17 am

Re: Test #2

Postby Roberto Gonzalez 1L » Sun Mar 17, 2019 5:54 pm

The key here is to use the Van't Hoff Equation to find K2 at the temperature 30 celsius. I got 1.471^-14. Then take the square root of Kw to solve for your hydronium concentration and take the -log of the value. This will result in your new neutral pH. Comparing to see wether 7 is larger (meaning basic) or smaller (meaning acidic) compared to your neutral pH is how you solve this.


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