## T1 and T2

$\ln K = -\frac{\Delta H^{\circ}}{RT} + \frac{\Delta S^{\circ}}{R}$

Jorja De Jesus 2C
Posts: 121
Joined: Sat Jul 20, 2019 12:15 am

### T1 and T2

Why is it lnk1 at T1 and lnk2 at T2? Are both K and T changing?

Alice Ma 2K
Posts: 52
Joined: Wed Nov 13, 2019 12:26 am

### Re: T1 and T2

K depends on T, so if one changes, so will the other.

JohnWalkiewicz2J
Posts: 103
Joined: Thu Jul 11, 2019 12:17 am
Been upvoted: 1 time

### Re: T1 and T2

Yeah remember that temperature changes also affect changes in equilibrium (K) which is why there is a seperate T1/K1 and T2/K2.

preyasikumar_2L
Posts: 101
Joined: Fri Aug 09, 2019 12:17 am

### Re: T1 and T2

The concentrations of reactants and products at equilibrium changes when temperature changes, so the value of K will also change when temperature changes.

Rodrigo2J
Posts: 102
Joined: Sat Jul 20, 2019 12:16 am

### Re: T1 and T2

Because of the equilibrium constant, K, is dependent on temperature, we write T1/K1 and T2/K2 to show that K will be a different value at a different temperature.

Trent Yamamoto 2J
Posts: 111
Joined: Sat Aug 17, 2019 12:18 am

### Re: T1 and T2

Since K is influenced by temperature, this is why there are separate K values for differing T values

Martina
Posts: 111
Joined: Thu Jul 25, 2019 12:16 am

### Re: T1 and T2

This equation lets you solve for K at different temperatures, so it can show you the change in the equilibrium constant between T1 and T2.

Sofia Barker 2C
Posts: 101
Joined: Wed Sep 18, 2019 12:21 am

### Re: T1 and T2

K values change with temperature, so the k value for one temperature will be different compared to a k value at another temperature. While pressure, volume, and concentration changes only shift the equilibrium of a reaction, temperature changes the actual k equilibrium value.