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### delta s

Posted: Sun Feb 16, 2020 6:29 pm
Why do we assume delta s naught is constant in the van't hoff equation?

### Re: delta s

Posted: Sun Feb 16, 2020 7:04 pm
delta S naught is the entropy of the reaction at standard conditions. Since standard conditions are defined, delta S naught will be a constant/always have the same value.

### Re: delta s

Posted: Sun Feb 16, 2020 7:07 pm
This is because delta S naught is the standard entropy of that reaction, therefore making it constant. We then have to include the temperature to show how the observed entropy can change depending on how you change the different parameters such as temp.

### Re: delta s

Posted: Sun Feb 16, 2020 7:14 pm
ΔS° is defined as entropy change in a set of standard conditions. ΔS° won't change for a given reaction unless those standard conditions do.

### Re: delta s

Posted: Sun Feb 16, 2020 7:15 pm
Delta S is constant in the Vant Hoff equation because the change in entropy of the system at equilibrium is constant. Delta S doesn't increase because it has reached its maximum.

### Re: delta s

Posted: Sun Feb 16, 2020 7:21 pm
Delta S won’t change under standard conditions.

### Re: delta s

Posted: Sun Feb 16, 2020 8:07 pm
It won't change unless standard conditions are changed

### Re: delta s

Posted: Sun Feb 16, 2020 8:19 pm
Because delta s won't change in those conditions!

### Re: delta s

Posted: Sun Feb 16, 2020 8:28 pm
Because standard conditions don't change !

### Re: delta s

Posted: Sun Feb 16, 2020 8:33 pm
Delta s does not change, both s values may change but the difference between final and intitial remains constant.