Andrew F 2L wrote:Can someone explain to me why we are taking the natural log of Temperature in Van't Hoff's equation? I'm confused as to what the equation also is trying to convey also because I was confused about the in class example. Thank you!
The reason you take ln(K) is because you are assuming that the reaction is at equilibrium, meaning delta G is equal to zero.
You have the two equations ∆G= ∆Gnot +RTln(Q) and ∆Gnot=∆Hnot-T∆S
At equilibrium, Q=K and ∆G=0
You can then solve for ∆Gnot and set the two equations equal to each other. This is what gives you the ln(k) in the equation. I hope that this helps!