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For 5G 13 and 5G 15, the textbook solutions manual keeps the product and reactant partial pressures in units of bar to calculate Q. Why isn't it necessary to convert to atmospheres? I calculated Q using bar and then again using atm and the values are different, so the reasoning can't be that they are equivalent or close to equivalent in value.
As stated before, bars are approximately equal to atmospheres, but in general this shouldn't matter as long as they are all in the same units. When you are calculating Q, you usually use the values without units because the partial pressures are representing the activities of each compound, which has no units. Hope this helps!
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