## Van't Hoff

$\ln K = -\frac{\Delta H^{\circ}}{RT} + \frac{\Delta S^{\circ}}{R}$

Haley Dveirin 1E
Posts: 101
Joined: Sat Jul 20, 2019 12:17 am

### Van't Hoff

One of the bullets on the thermodynamics outline says "Use a ‘Chemisty’ van't Hoff analysis to calculate ∆H°, ∆S° and ∆G°." Can someone explain this?

Alex Tchekanov Dis 2k
Posts: 118
Joined: Sat Aug 24, 2019 12:16 am

### Re: Van't Hoff

I believe this just means that you should be able to use the equation to solve for one of those if given to you as an unknown

William Chan 1D
Posts: 102
Joined: Sat Sep 14, 2019 12:15 am

### Re: Van't Hoff

I think we'll be given the other components, and solving for just one of those variables.