## Half reactions 6L.9

$\ln K = -\frac{\Delta H^{\circ}}{RT} + \frac{\Delta S^{\circ}}{R}$

asannajust_1J
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### Half reactions 6L.9

For 6L.9 ad 6L. 10, how do you know how the reaction will take place. In other words, how do you decipher which will be reduced and which will be oxidized when given potassium permanganate and FeCL2 react in an acidic solution. Would you use the standard cell potentials to determine the reaction that would be likely to occur?

405318478
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### Re: Half reactions 6L.9

The standard cell potentials are very helpful when the cell is spontaneous. The greater the magnitude of charge the stronger the reducer/oxidizer.