Half reactions 6L.9


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asannajust_1J
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Half reactions 6L.9

Postby asannajust_1J » Sun Mar 01, 2020 3:17 pm

For 6L.9 ad 6L. 10, how do you know how the reaction will take place. In other words, how do you decipher which will be reduced and which will be oxidized when given potassium permanganate and FeCL2 react in an acidic solution. Would you use the standard cell potentials to determine the reaction that would be likely to occur?

405318478
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Joined: Sat Jul 20, 2019 12:16 am

Re: Half reactions 6L.9

Postby 405318478 » Sun Mar 01, 2020 3:45 pm

The standard cell potentials are very helpful when the cell is spontaneous. The greater the magnitude of charge the stronger the reducer/oxidizer.

Natalie Do 3F
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Re: Half reactions 6L.9

Postby Natalie Do 3F » Sun Mar 07, 2021 7:50 pm

If E>0 aka positive or if K>1 a reaction favors the products and is spontaneous! Also, if E is very positive it is a great oxidizer and if E is very negative it is a strong reducer.


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