## Test 2 Calculate K after a temperature change

$\ln K = -\frac{\Delta H^{\circ}}{RT} + \frac{\Delta S^{\circ}}{R}$

Philip
Posts: 100
Joined: Sat Sep 07, 2019 12:16 am

### Test 2 Calculate K after a temperature change

Given that delta H reaction = 161 kJ/mol and K = 8.43 x 10^-12 for the reaction at 25 degrees C. Calculate K at 125 degrees C. Assume that delta H reaction and delta S reaction remain constant over this temperature range.

Idk what I did because somehow I ended up with a new K value of 6.808 x 10^-96

Julia Holsinger_1A
Posts: 50
Joined: Tue Feb 26, 2019 12:16 am

### Re: Test 2 Calculate K after a temperature change

make sure to set up the equation by first isolating ln(K2). So the equation would be: ln(K2)=(deltaH/R) (1/T1 - 1/T2) + ln(K1). Then plug in your numbers. I have found that when I don't isolate the ln(K2) first I get a strange answer.