Sapling #18

[lwon Dis2I]

For Sapling #18, how do you mathematically get rid of the ln of ln(K)?

[Sahaj Patel Lec3DisK]

You raise it to e! just like to get rid of -log you raised it to 10, you raise the ln() to e. Hope this helps!

[SainehaMaddineni_3I]

First isolate ln(K) to one side. Then, to get K, you should do e^(whatever is on the other side).

Here's an example of how to do it with some random numbers:
ln(x) = 2.3/4
x = e^(2.3/4)

[Victoria Dao 3G]

Hi! Ln is just log base e, so to get rid of it, just place whatever's on the opposite side of the equivalence sign as the power of e. Hope this helps!

[OwenSumter_2F]

It was strange to me when I did it and got a very large number, but trust your gut for the math and you should be good! :)

[Katelynn Shaheen 2C]

Raise it to the power of e like you would do for logs.

[Mary Shih 3J]

you neutralize the lnk by using e! so if lnk=2 then it will e^2

[Jordan Tatang 3L]

e^ln k cancels out the natural log and you're left with k.

[AustinMcBrideDis3L]

If you want to solve for what's inside the ln you need to take the reverse function of it: like diving is the reverse of multiplying, and - is to +.
The reverse of ln is e so make both sides of the equation e^ln(X)=e^#you get. This should help you solve it!

[Nishka Vipul 1J]

Hello,

For this one, you raise e to the value given for lnK. For example if lnK = 200 then K = e^200.

Hope this helps!

[Astha Sahoo 3I]

I would take the constant inside of the ln (like 40 if it was ln40) and then raise e to that power!

[Pranav Daggubati 3C]

First, Isolate the ln term and then take e to the power of that that ln(x) equals to get x

[Sophia Kalanski 1A]

raise it to the power of e!