Page 1 of 1

Oxidation of C2H2O4

Posted: Sat Jan 30, 2016 1:54 am
by Ranger Saldivar 2D
I was looking in the book and noticed that to oxidize C2H2O4 you need to identify the charges on the molecules. As far as I know C has a 4+ charge so why is it +3 on the left. Also once the oxidation takes place on the left it has a 4+ charge is there something I'm misssing?

Re: Oxidation of C2H2O4

Posted: Sat Jan 30, 2016 2:41 am
by Alexander Vong 3I
The oxidation number of an atom is derived from the bonds it makes from other atoms. An atom's charge is influenced by differences in electronegativity. For example, every C-H bond will decrease the oxidation state by 1, and every carbon bond to a more electronegative element will increase the oxidation state by 1.