Oxidation of C2H2O4
Posted: Sat Jan 30, 2016 1:54 am
I was looking in the book and noticed that to oxidize C2H2O4 you need to identify the charges on the molecules. As far as I know C has a 4+ charge so why is it +3 on the left. Also once the oxidation takes place on the left it has a 4+ charge is there something I'm misssing?
Re: Oxidation of C2H2O4
Posted: Sat Jan 30, 2016 2:41 am
The oxidation number of an atom is derived from the bonds it makes from other atoms. An atom's charge is influenced by differences in electronegativity. For example, every C-H bond will decrease the oxidation state by 1, and every carbon bond to a more electronegative element will increase the oxidation state by 1.