Course Reader Balance Example

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Course Reader Balance Example

Postby 904564128 » Mon Feb 01, 2016 3:52 pm

At the top of page 50 in the course reader, we are given an example of how to balance the half reactions to create a balanced redox reaction. I know Professor Lavelle said that if we know the half reactions are balanced, then the full one is, but I'm still confused since 2Fe (3+) + Cu Cu (2+) + 2Fe (2+) means there is a charge of +7 on the left and +6 on the right. So do we just decide to say it is balanced even though its actually not, but the half equations are?

Cristian Yanes 1L
Posts: 17
Joined: Fri Sep 25, 2015 3:00 am

Re: Course Reader Balance Example

Postby Cristian Yanes 1L » Mon Feb 01, 2016 4:30 pm

I have not referenced to the actual material you're talking about in the course reader, but based off the problem written in your question, both sides are +6 on charge (+6 on the left from the 2 Fe (3+) and +6 on the right from the Cu (2+) and then 2 Fe (2+)).

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