904564128
Posts: 21
Joined: Fri Sep 25, 2015 3:00 am

At the top of page 50 in the course reader, we are given an example of how to balance the half reactions to create a balanced redox reaction. I know Professor Lavelle said that if we know the half reactions are balanced, then the full one is, but I'm still confused since 2Fe (3+) + Cu $\rightarrow$ Cu (2+) + 2Fe (2+) means there is a charge of +7 on the left and +6 on the right. So do we just decide to say it is balanced even though its actually not, but the half equations are?

Cristian Yanes 1L
Posts: 17
Joined: Fri Sep 25, 2015 3:00 am

### Re: Course Reader Balance Example

I have not referenced to the actual material you're talking about in the course reader, but based off the problem written in your question, both sides are +6 on charge (+6 on the left from the 2 Fe (3+) and +6 on the right from the Cu (2+) and then 2 Fe (2+)).