Balancing reactions

Moderators: Chem_Mod, Chem_Admin

Marc Farah 3D
Posts: 22
Joined: Wed Sep 21, 2016 2:59 pm

Balancing reactions

Postby Marc Farah 3D » Wed Feb 01, 2017 1:35 pm

When we balance half reactions, and double the reaction, why do we not double the E(not)? Why is it kept constant but when flipped it, we must change the E to negative?

Brianna Wummer 2L
Posts: 19
Joined: Wed Sep 21, 2016 2:56 pm

Re: Balancing reactions

Postby Brianna Wummer 2L » Wed Feb 01, 2017 3:41 pm

Hi there! It isn't necessary to double the E(not) because E(not) is a fixed value. It does not depend on the the moles or the numbers of times the reaction occurs or anything. Hope that helps!

Posts: 10
Joined: Wed Sep 21, 2016 2:58 pm

Re: Balancing reactions

Postby Tiffany_Luu_1F » Sun Feb 05, 2017 3:07 pm

E is an intensive property so the amount does not matter.

Posts: 13
Joined: Wed Sep 21, 2016 2:58 pm

Re: Balancing reactions

Postby Veronica_Giap_1C » Sun Feb 05, 2017 4:04 pm

Can you/someone elaborate and explain the relation of the reaction being intensive applies to the number of moles reacting?

Emily Wang 1H
Posts: 26
Joined: Sat Jul 09, 2016 3:00 am
Been upvoted: 1 time

Re: Balancing reactions

Postby Emily Wang 1H » Sun Feb 05, 2017 4:17 pm

E(nought) of the entire cell is the standard reduction potential, which is the difference between the two E values of each half reaction, so if you're multiplying by a number when the moles increase, the difference is still the same.

Return to “Balancing Redox Reactions”

Who is online

Users browsing this forum: No registered users and 2 guests