Cell potential in class example

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HimadreeR
Posts: 5
Joined: Wed Sep 21, 2016 2:55 pm

Cell potential in class example

Postby HimadreeR » Sun Feb 05, 2017 8:55 pm

Hi,
The half reactions for Fe3+ + Cu ----> Cu2+ + Fe2+ was:
Fe3+ + e- ---> Fe2+ E0=0.77 V
Cu2+ + 2e- ---> Cu E0=0.34 V
To calculate the cell potential you would add the two, but flipp the sign for E0 of copper, which I understand. But why don't you multiply E0 of iron by 2 since the final balanced reaction would be:
2Fe3+ + e- ---> 2Fe2+

Thanks :)

Noor_Burney_1L
Posts: 13
Joined: Wed Sep 21, 2016 2:55 pm

Re: Cell potential in class example

Postby Noor_Burney_1L » Sun Feb 05, 2017 9:05 pm

You wouldn't multiply E0 of iron by 2 because E0 is an intensive property, which means that the E0 value itself does not change.


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